[2020] Canmore sized on 8 x 8 grid?

Originally posted by SysFader

We started by creating an 800 pixel x 800 pixel canvas divided into 8 x 8. So each square is 100 pixels x 100 pixels.

Because this is the grid given by Erlite in sneak peak (the size of the Closed Alpha map)

Afterwards we imported the map behind the grid and started attempting to find something relative we could measure to scale the map into the grid (purely out of curiosity). For this to work we had to find a way to convert pixel units into meters then meters into kilometres.

At first we tried using the overpass, but since overpasses can vary in length this was thrown out.

You can't rely on a constant when it is a variable.

Someone suggested using the baseball field. The general conciseness was that it is a "little league" size field.

From Home Base to First base is 60', there are 18.28 m in 60'.

We divided 1000 m by 18.28 m which is 54.7 (this means that 54.7 Home base to First Base lengths = 1 Km)

The length in pixels of one square is 100 pixels, so 100 divided 54.7 times = 1.8 pixels for the length of ONE LITTLE LEAGUE FIELD scaled into this canvas.

The same process was used for major league field, but I'll go ahead and type it out.

From Home Base to First base is 90' there are 27.4 m in 90'.

We divided 1000 m by 27.4 m which is 36.49 (36.5) (this means that 36.5 Home base to First Base lengths = 1 Km)

The length in pixels of one square is 100 pixels, so 100 divided 36.5 times = 2.7 pixels for the length of ONE MAJOR LEAGUE FIELD scaled into this canvas.

Also here's this for the cross check if you're curious:

2.7 pixels--------90 feet

____________= ______________

1.8 pixels--------60 feet

The sides of both equation = 1.5 so the scale is done correctly. One of the two is likely true.

We eagerly await your responses.

[EDIT: Trying to format the math equation correctly]