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I asked myself if the duration of the dodge or the speed of the cars edge during a dodge differ between different cars. In my opinion there are two possibilities:

1) All cars have the same "dodge duration". This would mean that the frontend of a longer car (batmobile) would have a higher velocity than the frontend of a shorter car (octane), because the circumference that an edge of a longer car has to travel in the same period is larger for a longer car than for a shorter car.

2) All cars frontends have the same speed during a dodge. This would mean that a dodge for a longer car would take longer than the dodge of a shorter car.

1) would mean, that longer cars could have an advantage while shooting because a higher velocity during a dodge would result in a harder shot. 2) would mean, that a shorter car could have an advantage because the dodge is finished faster and you have full control over your car earlier.
Does anyone know how this works?

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almost 6 years ago - /u/Psyonix_Cone - Direct link

You are correct, the ends of longer cars have a higher velocity than shorter cars when dodging. However the bulk of the impact force between the ball and the car comes from the extra forces that we add after the collision response is calculated by the physics engine, and these extra forces depend entirely on the relative linear velocity between the car and the ball. Angular velocity does not factor into the extra forces.

almost 6 years ago - /u/Psyonix_Cone - Direct link

Originally posted by HoraryHellfire2

So to verify, you're saying that the speed of the impact point matters, and thus longer cars do hit harder, but the difference is only minor due to the way physics are handled uniquely in the game, correct?

Yes, very minor. We basically just use the physics engine for resolving intersections. Restitution is mostly disabled (between the car and ball).