about 4 years
ago -
Shurenai
-
Direct link
It works in one of two ways. 1: If the players are separated by more than a certain distance (100~meters?), then the horde night will spawn zombies specifically appropriate for each player individually- This means for the gamestage of each individual player, and yes, it will spawn twice as many zombies- If you have the game set to a horde count of 8, each player will get 8 zombies, up to the servers max zombie count. (EG: If you have it set to a horde of 64, but max zombie count of 80, then each player would get 40~ at a time.)
2: If the two(or more) players are near eachother, then the game will add and multiply their gamestages together and come up with a combined value for the involved players, using that to determine what kind of zombies should spawn- And each player will still receive an amount of zombies appropriate to them up to the limit: Meaning if you have a horde count of 8, and 4 players, you'll have 32~ at a time.
As for how group gamestage is determined when two or more players are together, here's the math:
The result is a gamestage higher than either involved party member when it's just two players- But frankly, two players playing together typically results in a much stronger and more well defended base; so it's done this way for balancing reasons.
Edit: Given your circumstances, it may be better for your friend to either stay inside the walls and attack from afar and maintain traps, Or for him to go off and battle his own horde night.
2: If the two(or more) players are near eachother, then the game will add and multiply their gamestages together and come up with a combined value for the involved players, using that to determine what kind of zombies should spawn- And each player will still receive an amount of zombies appropriate to them up to the limit: Meaning if you have a horde count of 8, and 4 players, you'll have 32~ at a time.
As for how group gamestage is determined when two or more players are together, here's the math:
Originally posted by gamestage.xml: This is how the gamestage of a PARTY is calculated:
The gamestage of all (up to) 6 players is calculated.
The players are sorted by gamestage.
The highest GS number is multiplied by "startingWeight".
This then loops down the list and "startingWeight" is multiplied by "diminishingReturns" every time.
Example:
Players with GS 120, 30, 60, 91, 5, 80.
startingWeight= 1.7, diminishingReturns=0.5
So we get
120 * 1.70 = 204
91 * .85 = 77
80 * .42 = 34
60 * .21 = 13
30 * .82 = 24
5 * .11 = 1
... or a total party GS of 353
The result is a gamestage higher than either involved party member when it's just two players- But frankly, two players playing together typically results in a much stronger and more well defended base; so it's done this way for balancing reasons.
Edit: Given your circumstances, it may be better for your friend to either stay inside the walls and attack from afar and maintain traps, Or for him to go off and battle his own horde night.